(3x^2-60x+200)=0

Solution for (3x^2-60x+200)=0 equation:

(3x^2-60x+200)=0

We get rid of parentheses

3x^2-60x+200=0

a = 3; b = -60; c = +200;
Δ = b2-4ac
Δ = -602-4·3·200
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-20\sqrt{3}}{2*3}=\frac{60-20\sqrt{3}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+20\sqrt{3}}{2*3}=\frac{60+20\sqrt{3}}{6}
$